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Problem 309: Anton Bidlen - Fairy

bidlen(07.01.2014) Series Helpmate by Anton Bidlen with long bK trip and multi Bristols on h-file between bK and bRs.





309


1.Kg8 2.Kf7 3.Ke8 4.Kd7 5.Kc8 6.Kb7 7.Kxb6 8.Kxb5 9.Kc4 10.Kc3 11.Kd2 12.Ke1 13.Kf1 14.Kg1 15.Kh2 16.Kh3 17.Kh4 18.Kh5 19.Rh4 20.Rh2 21.Kh4 22.Kh3 23.Rh4 24.Rg4 25.Kh4  26.Kh5 27.Kh6 28.Rh5 Bf8# 
 

Comments  

 
+1 #1 Janos Mikitovics 2014-01-08 09:30
Please, look at this combination in Meredith form:

White Pg7 Pf6 Kf3 (3)
Black Ph7 Pg6 Pg5 Pf4 Rh4 Pg2 Rh2 Kg1 Bh1 (9)
ser-h#16

1.Rh4-g4 2.Rh2-h6 3.Kg1-h2 4.Kh2-h3 5.Kh3-h4 6.Kh4-h5 7.Rg4-h4 8.Rh4-h2 9.Kh5-h4 10.Kh4-h3 11.Rh6-h4 12.Rh4-g4 13.Kh3-h4 14.Kh4-h5 15.Kh5-h6 16.Rh2-h5 g7-g8=S #
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0 #2 Janos Mikitovics 2014-01-09 21:35
Here's another option:
White Pg7 Pf6 Ph5 Kf3 Sg2 (5)
Black Ph7 Pg6 Ph6 Pg5 Pf4 Rg4 Rh2 Kg1 Bh1 (9)
ser-h#21

1.Rh2*h5 2.Rh5-h2 3.h6-h5 4.h5-h4 5.h4-h3 6.h3*g2 7.Rh2-h6 8.Kg1-h2 9.Kh2-h3 10.Kh3-h4 11.Kh4-h5 12.Rg4-h4 13.Rh4-h2 14.Kh5-h4 15.Kh4-h3 16.Rh6-h4 17.Rh4-g4 18.Kh3-h4 19.Kh4-h5 20.Kh5-h6 21.Rh2-h5 g7-g8=S #
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0 #3 Janos Mikitovics 2014-01-09 22:08
...and with KoBul Kings:
White Ph5 Kf3 Sg2 (3)
Black Ph6 Pg5 Pf4 Rg4 Rh2 Kg1 Bh1 (7)
ser-h#10
KoBul-Kings

1.Rh2-h4 2.Kg1-h2 3.Kh2-h3 4.Rg4*g2[f3=rS] 5.Rh4*h5[f3=K] 6.Rh5-h4 7.Rh4-g4 8.Kh3-h4 9.Kh4-h5 10.Rg2-h2 + Kf3*g4[h5=rR] #
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0 #4 Janos Mikitovics 2014-01-11 21:08
:-)
White Ph5 Bc3 Kf3 Pg2 (4)
Black Ph7 Pg6 Ph6 Pg5 Pf4 Rg4 Rh2 Kg1 Bh1 (9)
ser-h#21
Mirror-Circe

1.Rh2*h5 2.Rh5-h2 3.h6-h5 4.h5-h4 5.h4-h3 6.h3*g2[+wPg7] 7.Rh2-h6 8.Kg1-h2 9.Kh2-h3 10.Kh3-h4 11.Kh4-h5 12.Rg4-h4 13.Rh4-h2 14.Kh5-h4 15.Kh4-h3 16.Rh6-h4 17.Rh4-g4 18.Kh3-h4 19.Kh4-h5 20.Kh5-h6 21.Rh2-h5 g7-g8=S #
Quote
 

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