Problem 781: Francesco Simoni - Helpmate |
(22.12.2016) The Italian Maestro presents a nice helpmate with interesting dual avoidance and pinmates.
781. Francesco Simoni (Italy)
22.12.2016
H#2 3 Sol. (11+13)
1.b3xa2 Qb5 2.g3xh2 Sxf2#
1.b6xa5 Rxa5 2.Sg7 Sxg3# 1.f6xg5 Rxg5 2.Rxd6 Sxc3# Three black pieces are pinned. White unpins one of these in turn, which decides B2 and the mate.
Cyclical double dual avoidance in B2 for direct unpin. Double pin mates with cycle of double pins. (Author) |
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Comments
8/5p2/1p3p2/7s/R2bkqR1/2pr2p1/S5KP/1Q1S1S2 (7+11)
H#1.5 3 solutions 1..., Rg5 2.Sc1, Sxc3#
Ra5 2.Sg7, Sxg3#
Qb5 2.gxh2, Sf2#
Better form, does not improve the strategic content of course.
About Rodolfo's comment, I agree that B1 is poor, but its the only way I found to do the double dual avoidance with homogenous strategy. Incidentally, I think a helpmate in 1.5 is nothing.
H#1.5 3 sol.
1...Qb1-b5 2.g3*h2 Sd1-f2 #
1...Ra4-a5 2.Sh5-g7 Sf1*g3 #
1...Rg4-g5 2.Sa2-c1 Sd1*c3 #
The question is how to add a better B1.
Also h#2 that are badly diluted h#1.5 are nothing.
Furthermore, how would you highlight the hypothetical anti-triple?
1.bxa2, Qb5 (Ra5?, Rg5?) etc. ?
The Vitaly's problem is nothing more than a diluted (9+9)H#1.5.
When the same piece move twice to take a guard, I could consider it a weakness, but not certeanly a diluted H#2. A problem should be judged for the whole content, and Vitaly's problem, like mine, is appreciable in its Whole.
Yes. It has a similar idea but not an anticipation I think.
H1.5 is not enought, it's obvious to search always a B1 move, also when the B1 piece does nothing in all ather solutions. I think that to move a piece with the simple purpose of taking a guard could be a weakness, but a problem must be judged in its whole.
1.bxa2 Qb5 2.gxh2 Sxf2‡ (2.Sg7? 2.Rxd6?)
1.bxa5 Rxa5 2.Sg7 Sxg3‡ (2.Rxd6? 2.gxh2?)
1.fxg5 Rxg5 2.Rxd6 Sxc3‡(2.gxh2? 2.Sg7?)
It is truly dual avoidance: each unpinned piece guards two of the threee squares of mate in turn and this specifies B2.
Fully agree, trivial black moves throughout the solution detract a lot in hms of any lenght.
This was the first matrix I had found. But I could not find a correct position in two moves.
Simple keys certainly do not beautify a problem, but it can not be said thay diminish its value. In this problem three black pieces are involved in the double pins and in the dual avoidance. I did not see how to implement more complex strategies in B1 and it is very much that I have succeeded in specifying the three complete solutions.
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