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Problem 781: Francesco Simoni - Helpmate
francesco.simoni(22.12.2016) The Italian Maestro presents a nice helpmate with  interesting dual avoidance and pinmates.

 

 

 

 

 

 

781. Francesco Simoni (Italy)
22.12.2016
781
    H#2          3 Sol.           (11+13)  
 
 
1.b3xa2 Qb5 2.g3xh2 Sxf2#
1.b6xa5 Rxa5 2.Sg7 Sxg3#
1.f6xg5 Rxg5 2.Rxd6 Sxc3#
 
 
Three black pieces are pinned. White unpins one of these in turn, which decides B2 and the mate.
Cyclical double dual avoidance in B2 for direct unpin. Double pin mates with cycle of double pins. (Author)
 

Comments  

 
+1 #1 Vitaly Medintsev 2016-12-22 21:22
Compare to:
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0 #2 Rodolfo Riva 2016-12-23 08:52
Very poor content of the Black moves and many unpleasant captures. It is a ficticious h#2.

8/5p2/1p3p2/7s/R2bkqR1/2pr2p1/S5KP/1Q1S1S2 (7+11)
H#1.5 3 solutions 1..., Rg5 2.Sc1, Sxc3#
Ra5 2.Sg7, Sxg3#
Qb5 2.gxh2, Sf2#
Better form, does not improve the strategic content of course.
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+1 #3 Francesco Simoni 2016-12-23 10:07
Thank to both for the comments. I already knew the nice Vitaly's problem, but it's not an anticipation, in my opinion, since it has a different pattern and especially because its mechanism doesn't offer double dual avoidance as it does in my problem.
About Rodolfo's comment, I agree that B1 is poor, but its the only way I found to do the double dual avoidance with homogenous strategy. Incidentally, I think a helpmate in 1.5 is nothing.
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+2 #4 Seetharaman Kalyan 2016-12-23 12:31
Rodolfo's scheme!


H#1.5 3 sol.

1...Qb1-b5 2.g3*h2 Sd1-f2 #
1...Ra4-a5 2.Sh5-g7 Sf1*g3 #
1...Rg4-g5 2.Sa2-c1 Sd1*c3 #

The question is how to add a better B1.
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-1 #5 Rodolfo Riva 2016-12-27 14:59
To #3
Also h#2 that are badly diluted h#1.5 are nothing.
Furthermore, how would you highlight the hypothetical anti-triple?
1.bxa2, Qb5 (Ra5?, Rg5?) etc. ?

The Vitaly's problem is nothing more than a diluted (9+9)H#1.5.
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+2 #6 Vitaly Medintsev 2016-12-27 15:18
Yes, I agree that my h#2 is a diluted h#1.5 because the first black's move is not sufficient but I don't consdider the genre h#1.5 quite sufficient, too.
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0 #7 Francesco Simoni 2016-12-27 16:10
Quoting Rodolfo Riva:
To #3
The Vitaly's problem is nothing more than a diluted (9+9)H#1.5.

When the same piece move twice to take a guard, I could consider it a weakness, but not certeanly a diluted H#2. A problem should be judged for the whole content, and Vitaly's problem, like mine, is appreciable in its Whole.
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+1 #8 Seetharaman Kalyan 2016-12-27 17:49
Quoting Francesco Simoni:
Thank to both for the comments. I already knew the nice Vitaly's problem, but it's not an anticipation, in my opinion, since it has a different pattern and especially because its mechanism doesn't offer double dual avoidance as it does in my problem.

Yes. It has a similar idea but not an anticipation I think.
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0 #9 Francesco Simoni 2016-12-28 08:11
Quoting Rodolfo Riva:
The Vitaly's problem is nothing more than a diluted (9+9)H#1.5.

H1.5 is not enought, it's obvious to search always a B1 move, also when the B1 piece does nothing in all ather solutions. I think that to move a piece with the simple purpose of taking a guard could be a weakness, but a problem must be judged in its whole.
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0 #10 Francesco Simoni 2016-12-28 08:19
Quoting Rodolfo Riva:
To #3
Also h#2 that are badly diluted h#1.5 are nothing.
Furthermore, how would you highlight the hypothetical anti-triple?
The cyclical dual avoidance is generated by the direct unpins.
1.bxa2 Qb5 2.gxh2 Sxf2‡ (2.Sg7? 2.Rxd6?)
1.bxa5 Rxa5 2.Sg7 Sxg3‡ (2.Rxd6? 2.gxh2?)
1.fxg5 Rxg5 2.Rxd6 Sxc3‡(2.gxh2? 2.Sg7?)
It is truly dual avoidance: each unpinned piece guards two of the threee squares of mate in turn and this specifies B2.
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0 #11 Rodolfo Riva 2016-12-28 11:17
To#7. "... a problem must be judged in its whole."

Fully agree, trivial black moves throughout the solution detract a lot in hms of any lenght.
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