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Problem 761: Zivko Janevski - Helpmate
zivko.janevski(07.11.2016) Another welcome contribution from the Macedonian helpmate expert, this time a HOTF.
 
 
 
 
 
 
 
 
 
 
 
761. Zivko Janevski (Macedonia)
07.11.2016 
760
H#2            4 Sol.          (4+7)
 
 
1.Bc7 exf5+ (A) 2.Kd6 Rd5#
 
1.Sf8 Rxf5 (B) 2.Sd7 Bd5#
 
1.f6 Bc6 2.Qf7 exf5# (A)
 
1.Kf6 Bc8 2.Qg7 Rxf5# (B)
 

 

A setting of two pairs of thematically connected solutions

with mates on the same square and change function

of the white moves exf5/Rxf5 in a Meredith position. (Author)
 

Comments  

 
+2 #1 Seetharaman Kalyan 2016-11-07 18:28
Well.. there are two pairs of mates and hence it could be classified as HOTF, but the relationship between the two pairs make it a wonderful whole!
Quote
 
 
+1 #2 Miodrag Mladenovic 2016-11-09 19:36
Beautiful problem. Excellent position. Way to go in modern helpmates.
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