Problems 1028 & 1029: Mikhail Gershinsky & Aleksandr Pankratiev - Helpmates |
(31.12.2019) Few more originals in last minutes of the year. Happy to present two nice helpmates from the Russian masters with apologies for the belated publication. With this I have published all helpmate originals I have received. If I missed any please resend. (Seetharaman)
1028. Mikhail Gershinsky (Ukraine) &
Аleksandr Pankratiev (Russia)
H#2 5 sol. (6+10)
1. S7xf5 Be5 2. Kxe5 Re6#
1. Kxe3 Re6 2. Kd3 Rd5# 1. S3xf5 Bxc2 2. Kd5 e4# 1. Rb2 Rf4 2. Ke5 Bxb2# 1. Rxa1 Rc3 2. Ba2 Bxc2# Will the above be better as a four solution helpmate? (Seetharaman)
1029. Mikhail Gershinsky (Ukraine) &
Аleksandr Pankratiev (Russia)
H#3.5 b) Rd8-e7 (3+13)
a) 1... Bxb7! 2. Kf4+ Kxh2 3. Qe3 Bf3 4. e5 Rxf7#
b) 1... Rxb7! 2. Qc6 Rb3 3. Ke4 Rf3 4. Be5 Bxc6#
|
KOBULCHESS.COM
site for chess composition
General editor:
Diyan Kostadinov
Co-editor:
Seetharaman Kalyan