Problems 410 & 411: Nikola Predrag - Helpmate |
410. Nikola Predrag (Croatia)
19.06.2014
![]() H#2 (4+13)
b)#>bKc8 c)#>bKg7 d)#>bKg1 e)#>bKc2 [f)#>bKc6 & wPd3...]
Solutions: a) 1.Ba3 d4 2.Bc5 d5# b) 1.Be7 d6 2.Bd8 d7# c) 1.Bg5 d8Q 2.Bh6 Qf6# d) 1.Bf4 Qh4 2.Bh2 Qe1# e) 1.Be5 Qg3 2.Bb2 Qd3# Two ten-step Rundlaufs: Bl.bishop: b2-a3-c5-e7-d8-g5-h6-f4-h2-e5-h2. W.Pawn:/Q: d3-d4-d5-d6-d7-d8-f6-h4-e1-g3-d3. (Author) The length of the Rundlauf makes the task, also the consistency of the twinning without any superflous white officer in any of the phases. The captureless play ensures that only the BK, WP/Q changes position during the play enabling the return to the start position (Author) The next problem shows even longer Rundlaufs. The twinning is not consistent at twin (g), but worthwhile considering the length of the round-trip !. (Seetharaman)
411. Nikola Predrag (Croatia)
19.06.2014
![]() H#2 (7+9)
b)#>bKa8 c)>#bKh6 d)>#bKe1 e)>#bKg3 f)>#bKg8,
g)>#bKc1 & bPh4-f3 h)>#bKd4 [a)bKc6, Pf3-h4 & wQ=wP...]
Solutions: a) 1.Bb6 b4 2.Ba5 b5#
b) 1.Bc7 b6 2.Bb8 b7# c) 1.Bf4 b8Q 2.Bg5 Qh8# d) 1.Be3 Qh6 2.Bf2 Qc1# e) 1.Bg1 Qf1 2.Bh2 Qf3# f) 1.Bd6 Qh5 2.Bf8 Qh7# g) 1.Ba3 Qh4 2.Bb2 Qe1#
h) 1.Kc4 Qb1 2.Bd4 Qb3#
15-square Rundlauf by the Black bishop and 16 square Rundlauf by the WP/Q. (Author) |
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Comments
It will be not easy to judge HELPmate section in KoBullChess.com 2014 IT. Lets HELP the judge by our comments!
Here is the bulletin with the award:
wfcc.ch/.../...
show very interesting potential of the "Continued Play" twinning.
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