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Задача 575: Pierre Tritten - Fairy (KoBul Kings, Symmetry AntiCirce)
pierre.tritten(30.04.2015) Фантастична задача от Пиер Тритон с интересно комбиниране на фееричните условия КоБул Цар и Симетрично Анти Цирце с динамична игра и богато тематично съдържание!
 
 
 
 
 
 
 
 
575
 
a) 1.Bxf3-c6(c2=rR) rRxc6-f3(h2=rB) 2.rBc7 rRxf7-c2(c7=rS)#
b) 1.Rxb3-g6(c2=rB) rBxg6-b3(h2=rR) 2.rRh7 rBxf7-c2(h7=rS)#
 
White KoBul King mate after switchback
Interchange of function between white officers (passive sacrifice / passive anticipatory guard)
Diagonal-orthogonal echo, model mates
(Author)
 
KoBul Kings:When a piece (not a pawn) of his own side is captured, a King transforms into a Royal piece of the same type as the captured one. When the King is in the form of any Royal piece and there is a capture of one of the pawns of his own side, he becomes a normal King again.Captures are illegal if they result in self-check by the transformed King. Castling is allowed only if the KoBul King is on his initial square in the form of a normal King and if he has not already moved; however he may already have been transformed. 
Symmetry Anti Circe: The capturing unit goes to a square which is determined symmetrically by the central point of the chessboard allowing rebirths all around the board.
 

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