Problem 279.1: Diyan Kostadinov & Nikola Predrag - Fairy (KoBul Kings) |
(17.11.2013) I composed this problem last night with SneK Chess, but today I decide to publish it as a KoBul Kings problem (both conditions working in the same way in case of capture of Knights only), because all transformations here are of the Kings, so this present the KoBul Kings condition more full than SneK Chess where all pieces can be transformed. Update: After publication of the problem was found that it can be improved. Here you can see the version 279.1. which replace the initial problem for the tourney.
a) bl. 1.Se8! & 1.Sxe8(bK=rS) 2.Ka7+ Qxe8(wK=rS)= b) bl. 1.Sb7! & 1.Sd5 2.Kxb7(bK=rS)+ Rxd5(wK=rS)= Active white and black sacrifices, miniature, non standart stipulation, nice twin form. (Author)
KoBul Kings - When a piece (not a pawn) of his own side is captured, a King transforms into a Royal piece of the same type as the captured one. When the King is in the form of any Royal piece and there is a capture of one of the pawns of his own side, he becomes a normal King again. |
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Comments
But Kjell is right that it can be done with two promotions (with stipulation HS=2.5), unfortunatelly with dual in 1...d1R solution.
So there are two possibilities: to make the problem with not so usual stipulation B1&Ser-S=2 to keep nice black Knight moves (with good twin - exchange two type pieces), or to make it with more usual condition HS=2 with twin moves bS and to have two promotions.
Here is the version: prntscr.com/26na3b
So it is the matter of taste which is better - nice moves by the bS in the original or two promotions in the version.
What the is your opinion?
Another drawback is that after B1, it works also as a ser-h=2 with reversed colors. I would surely prefere something like:
W:Kc8,Sc4; B:Ka8,Sc3,Pd2
hs=3,Kobul,2 sol.
Probably I was not worked enough on the problem before the publication to miss such a clever improvement...
About your question for the stipulation - in such kind stipulations where one side make 1 or more moves before the main stipulation it is understandable that these first moves are "help" because after them the main condition should be prepared.
How would such a stipulation, B1&Ser-S=2, be recognized by Popeye?
"B1/Series#5" is meaningless to Popeye.
Protocol h1
White Pa2 Kf1
Black Pc3 Ba1 Kh1
Stipulation 1->SER-#6
Option NoBoard NoThreat Variation
Popeye Windows-32Bit v4.63 (1431 MB)
1.Ba1-b2 1.a2-a4 2.a4-a5 3.a5-a6 4.a6-a7 5.a7-a8=R 6.Ra8-h8#
1.Kh1-h2 1.a2-a4 2.a4-a5 3.a5-a6 4.a6-a7 5.a7-a8=Q 6.Qa8-g2#
solution finished.Time = 0.031 s
As can be seen, black has a third choice of first move 1.c2 after which white cannot mate in 6 moves.
HZg74 help-targetsquare-g7 in 4 moves
S+2 self-check in 2 moves
SER-+7 series-check in 7 moves
SEMI-R+4 semi-reflex-check in 4 moves
x3 Capture in 3 moves
SER-%4 series-Win_a_Piece in 4 moves
H##!4 help-"gegenmatt" in 4 moves
SER-H##3 series-help-"beidmatt" in 3 moves
2->ser-h#4 White makes 2 moves, then ser-h#4
h003 help-castling in 3 moves
ser-ct10 Series-direct circuit (switchback) in 10 moves (of W piece)
h3 help exchange place in 3 moves (Bl helps W swap 2 pieces from diagram)
h~1 any helpmove
pser-h#6 Parry series helpmate in 6
phser-s#6 Parry series selfmate in 6 (parry moves are help moves)
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