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Problem 1001: Klaus Forster - Twomover
klaus.forster(13.11.2019) Welcome to Klaus Forster! He present us a nice twomover with reciprocal changes and flight-giving key.
 
 
 
 
 
 
 
 
 
1001. Klaus Forster (Germany)
1001
#2* v                                    (11+9)
 
Set: 1...Bd3 2.exd3#
 
Try: 1.Bb4? (2.Qd4)
1...Sxe2/ bxc5b 2.Qxb3A/ Qd5B#, but 1...Bd3!
 
Sol: 1.Bc3! (2.Qd4)
1...Sxe2a/ bxc5b/ Bd3/ Kxc3 2.Qd5B/ Qxb3A/ Qxd3/ Qd4#
 
Reciprocal change of mates, with an additional change after 1...Bd3 and two flight-giving first moves. I think it is a nice problem which can gladden the solvers. (Author)
 

Comments  

 
0 #1 Seetharaman Kalyan 2019-12-10 07:57
A black pawn c7 of Sc8 will also work, but composers probably dont mind using stronger black force in direct mates!
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+1 #2 Kostas Prentos 2019-12-10 16:31
Plus a bPc7, instead of the bSc8, would restrict the mobility of the wRb7. I don't know the aesthetics of direct twomovers, but I would probably prefer the Knight, too.
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0 #3 Seetharaman Kalyan 2019-12-10 18:19
Quoting Kostas Prentos:
Plus a bPc7, instead of the bSc8, would restrict the mobility of the wRb7. I don't know the aesthetics of direct twomovers, but I would probably prefer the Knight, too.

Thanks Kostas. You are right of course.
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