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Problem 850: Mikhail Gershinsky & Аleksandr Pankratiev - Helpmate
michael.gershinski(30.0aleksandr.pankratiev9.2017) The Ukraine - Russian tandem provides an excellent Zilahi with mates on the same square.
 
 
 
 
 
 
 
 
850. Mikhail Gershinsky (Ukraine) &
Аleksandr Pankratiev (Russia)
850
H#3        2 sol.        (5+12)
 
1.Sxd3 Bxb5 2.Sf4 Bxe2 3.Be4 Bg4#
1.Rxa4 d5 2.Rg4 Rd4 3.Be5 hxg4#
 

Comments  

 
+4 #1 Frank Richter 2017-10-03 12:18
No Zilahi here in my opinion - this would require to capture the wPh3 in solution 1.S:g3 or a mate by the wRd3 after 1.R:a4.
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+2 #2 Seetharaman Kalyan 2017-10-04 06:32
Quoting Frank Richter:
No Zilahi here in my opinion - this would require to capture the wPh3 in solution 1.S:g3 or a mate by the wRd3 after 1.R:a4.


You are right Frank Richter. My apologies to the authors. It was me who wrongly added Zilahi to the theme !
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