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Problem 846: Petko Petkov - Fairy (ConditionsUntilPly, Anti-Andernach, Lion, Locust)
petko.petkov(17.09.2017) A fantastic fairy problem in modern style and rich thematic complex shown here for the first time! Deep and instructive explanations by the bulgarian top composer.
 
 
 
 
 
 
 
 
 
 
 
846.1
 
a) 1.e8=bB! (X) Qxf3! 2.f8=bQ!(A) Qc6 =wQ
    3.Qa4+ Bxa4#; [2.f8=bR?(B), 2.f8=bLO?(C)]
 
b) 1.e8= bS! (Y) Qxc2! 2.f8=bR!(B) Qf5=wQ
     3.Qd7+ Sd6#; [2.f8=bLO?(C), 2.f8=bQ?(A)]
 
c)  1.e8= bLI! (Z) Qxg2! 2.f8=bLO(C) Qg8 =wQ
     3.Qh8+ LIxh8#;  [2.f8=bQ?(A),2.f8=bR?(B)]
 
Thematic complex
 
   1. Super AUW, realized in three phases after a cyclic six-fold promotions of the white Pawns e7, f7, that form black batteries! This idea is combined here with a double cyclic Anti -dual after promotions of the rear battery - pieces! This idea & mechanism are shown for the first time! Here's the cyclic formula:
               a) 1.X!- 2.A! B? C?
               b) 1.Y! - 2.B! C? A?
               c)  1.Z! - 2.C!A? B?
   2.The black moves: a) 1...Qxf3!; b) 1...Qxc2!; c) 1...Qxg2! aim to:  Keep the black color for the black Queen; to open a line for the white Locust.
   3.During the play the black Q makes a record number of moves - a total of 9 in the three phases!
   4.Here ConditionsUntilPly=4,  means that condition Ant-Andernach is valid only for the first 4 half-moves (plies) i.e. - until the second move of white and black. Then the remaining 2 half - moves (the 3rd move of white and black) are performed as orthodox half-moves.
 
   Important note: Some explanations are needed here regarding option  ConditionsUntilPly=4 used in this problem. The story of this kind of fairy element is very interesting.
   In fact, the beginning was put by the traditional 12th Belgrade Problem Chess Festival 2017 (26th-28th May 2017). The Serbian organizers, who have always been authors of very interesting events and competitions, this time offered in Belgrade Internet Tourney 2017 the following very fresh, non-standard theme: Group C – HS# Max2.5, 2 Solutions; Thematicondition: Help-selfmate Max with the help-play before the last two half-moves presenting S#1 Maximummer (Black has to play the geometrically longest move). No other fairy conditions or pieces are allowed. The theme was illustrated by the following example: White: Ka1, Rc8 (2); Black: Kh6, Pa2, Pb3, Pe2, HS#2.5 Max., 2 solutions: I. 1...e1B 2.Rf8 Bh4 and now white and black are required to play in the condition Maximummer: 3.Rf6+ The final is the longest (geometric) move of the black: 3...Bxf6#; II.1...e1R+ 2.Rc1 Rh1 and here it follows: 3.Rb1 Rxb1#.
   After the tournament was announced, I asked WinChloe's author, Christian Posison, whether it was possible to create a computer program to solve problems from type HS#2.5 Max? I was extremely surprised when Poisson wrote to me after a day that he had already created a program that had much more potential and after a few days of testing he would include it in the new version of WinChloe at that time 3.36! (By the way, the term "ply", which you will find later, means half-move. For example, an orthodox #2 has three half-moves (plies): the white key - move, the black  defense, and the white mating-move. A H#2 has 4 half-moves (plies), a HS#3 has 6 half-moves (plies) and so on.)
    
   In brief, the essence of the novelty was explained by its inventor - Poisson, in "Readme" (in May 2017)of the WinChloe version 3.36:
"Two new options are programmed, allowing to indicate from which ply, or until which ply, fairy conditions are taken into account.
These options, to write in the "twin" field, are: Conditionsfromply=n (or in French: Conditionsapartirde=n) and Conditionsuntilply=n (or in French: Conditionsjusqua=n), "n" being the number of plies.
For example :Conditionsfromply=5 means that the conditions are taken into account only from the 5th ply (the 3rd white move for a direct, a self or a help-self problems) and the 3rd black move for a help - problems.Conditionsuntilply=6 means that the conditions are taken into account only until the 6th ply (the 3rd black move for a direct, a selfor a help-self problems  and the 3rd white move for a help - problems).
It is possible to combine both options (write them on to different lines).
 
IMPORTANT: THESE OPTIONS WORK WITH "SIMPLE" CONDITIONS (Maximum, Minimum, Circe, Sentinelles...), BUT CAN (MAYBE) GIVE UNEXPECTED RESULTS WITH CONDITIONS ASKING MORE COMPLICATED CALCULATIONS. THEY DON'T WORK WITH CONDITIONS WHOSE EFFECTS ARE NOT CALCULATED AT EACH MOVE (Chinois...)"
For more information you can read Readme of the version 3,36 (the Readme - file, named “readme.txt” is in the “C:\WinChloe” folder).
(Author)
 
Anti-Andernach: A piece (excluding King) changes its color after any non-capturing move. After capture, the piece retains its color. Rooks on a1, h1, a8 and h8 can be used for castling, provided the usual other rules for that move are satisfied. After castling, Rooks do not change color. If White makes a non-capturing move with neutral or halfneutral piece, that piece becomes black and vice versa.
Lion (LI): Hops on Q-lines over any one unit (the hurdle) to any square beyond the hurdle.
Locust (L): a piece which moves only to capture. It lands on the same squares as a grasshopper, but the arrival square must be empty, because the locust captures its hurdle.
 

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