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Problem 801 to 804: Аleksey Ivunin & Аleksandr Pankratiev - Helpmate
alexey.ivuninaleksandr.pankratiev(23.01.2017) Another set of delightful helpmates from the Russian experts!
 
 
 
 
 
 
 
 
 
 
 
 
 
 801. Аleksey Ivunin &
Аleksandr Pankratiev (Russia)
 
791
H#3                                 (5+12)
b) Se6-d2   c) Pb2-c2
 
 
a) 1.bxc1=R+ Kd2 2.Rxc3 Sxd3 3.Rc6 Be5 #
b) 1.bxa1=B Sxd7 2.Bxc3 Sb8 3.Be5 Rc6 #
c) 1.Kxc5 Rxb1 2.Kc4 Rxb3 3.Sc5 Rb4 #
 
Paradox Zilahi.  Duplex-tema (Authors)
 
  
802. Аleksey Ivunin &
Аleksandr Pankratiev (Russia)
 
792
H#3.5        2 sol.        (4+8)
 
1...Ka4 2.Rc4+ bxc4+ 3.Kc5 Kb3 4.Sd6 Bf2 #
1...Bh4 2.Sa3 Bxf6 3.Sc4 Bc3 4.Rd6 bxc4 #
 
 
803. Аleksey Ivunin &
Аleksandr Pankratiev (Russia)
 
793
H#3.5       b) bKh8        (5+16)
 
a) 1...Bxd2 2.Kb6 Bxc3 3.Kc5 Bd2 4.Kd6 Bb4 #
b) 1...Rxd2 2.Bg6 Rxf2 3.Kh7 Rd2 4.Kh6 Rh2 #
 
Mutual battery formation and line clearance! (Seetharaman)
 
 
804. Аleksey Ivunin &
Аleksandr Pankratiev (Russia)
 
794
H#3.5       b) Bb1-a8        (3+5)
 
a) 1...Bc2 (Rf7?)  2.Ke3(Rcd1?) Bd1 3.Rc2 Rf7 4.Rd2 Rf3#
b) 1...Rf7+ 2.Ke5 Bb7 (Bc6?) 3.Rc6 Bc8 4.Rd6 Rf5 #
 
Echo mates!
 

Comments  

 
+1 #1 Yuri BILOKIN 2017-02-27 12:59
v802
8/5n2/2p2p1r/3k1P2/1K2n3/1P6/7B/2q5

H#3.5 2 sol. (4+7)
1...Ka4 2.Qc4+ bxc4+ 3.Kc5 Kb3 4.Sed6 Bg1#
1...Be5 2.Sfd6 Bxf6 3.Sc4 Bc3 4.Rd6 bxc4#
Quote
 
 
0 #2 Seetharaman Kalyan 2017-02-28 18:53
Nice improvement by Yuri Bilokin, adding a a different knight move to d6, improving the unity.


H#3.5 2 sol. (4+7)

1...Ka4 2.Qc4+ bxc4+ 3.Kc5 Kb3 4.Sed6 Bg1#
1...Be5 2.Sfd6 Bxf6 3.Sc4 Bc3 4.Rd6 bxc4#
Quote
 

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