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Problems 715 & 716: Anton Bidlen - Helpmate
anton.bidlen(24.03.2016) Two interesting helpmates from Anton Bidlen. The dance of the two kings is especially pretty!
 
 
 
 
 
 
 
 
 
 
715. Anton Bidlen (Slovakia)
24.03.2016
715
H#2          3 sol.         (5+5)
 
 
1.Sd2 Rxc3 2.Se4 Sc7#

1.Bg6 Kb3 2.Be4 Rd6#

1.Rg4 f5 2.Re4 Rc5#

 

Three selfblocks on 'e4' and three different mates, two by the same white piece. (Author)

 

 

716. Anton Bidlen (Slovakia)

24.03.2016

716

H#8.5                         (9+7)

 

1...b4+! 2.Ka4 Kb2 3.Kxb4 Ka2 4.Kc3 Ka3 5.Kd2 Kb4

6.Kxe3 Kxb5 7.Kxe4 Kc6 8.Kxf5 e4+ 9.Kxe6 Bc4#

 

Dance of two Kings. Black king returns to white king square! (Author)

 

Comments  

 
+2 #1 Yuri BILOKIN 2016-04-19 18:29
715. You can do without taking a rough 1 ... Rxc3. If the author of such a possibility does not see, I will inform you.
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0 #2 Seetharaman Kalyan 2016-04-20 10:44
Quoting Yuri BILOKIN:
715. You can do without taking a rough 1 ... Rxc3. If the author of such a possibility does not see, I will inform you.

Good observation Yuri Bilokin! I too found a setting but let us wait for the author to respond.
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0 #3 Seetharaman Kalyan 2017-01-19 11:07
Yuri Bilokin... can you please give your version?
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0 #4 Yuri BILOKIN 2017-01-19 16:08
v.715 8/8/2R1N3/3kB3/5P2/5p2/1nK1b1r1/3n
8/8/2R1N3/3kB1r1/1p3P2/5n2/1nK5/5b2
Quote
 
 
0 #5 Yuri BILOKIN 2017-01-19 16:31
Quoting Yuri BILOKIN:
v.715 8/8/2R1N3/3kB3/5P2/5p2/1nK1b1r1/3n
8/8/2R1N3/3kB1r1/1p3P2/5n2/1nK5/5b2

v.716 8/5p2/2p2Pp1/1kp2pP1/5P2/3K1P2/2P2P2/6B1
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0 #6 Seetharaman Kalyan 2017-01-19 16:43
Yuri Bilokin version for 715.



This avoids the capture on c3, but uses an extra black man. Perhaps it is a question of choice.

His version for 716 is however a great improvement. Solution is same.


H#8.5

1...c2-c4 + 2.Kb5-b4 Kd3-c2 3.Kb4*c4 Kc2-b2 4.Kc4-d3 Kb2-b3 5.Kd3-e2 Kb3-c4 6.Ke2*f3 Kc4*c5 7.Kf3*f4 Kc5-d6 8.Kf4*g5 f2-f4 + 9.Kg5*f6 Bg1-d4 #
Quote
 

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