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Problem 668: Bruno Colaneri - Helpmate
bruno.colaneri(23.12.2015) Another helpmate from the Italian author Bruno Colaneri has an interesting twin.
 
 
 
 
 
 
 
 
 
 
 
668. Bruno Colaneri (Italy)
23.12.2015
668a
H#2     b) Remove Sd5    (4+6)
 
 
a) 1.Bd4 c4 2.Se3 Sf2#

b) 1.Qd4 Kg6 2.Re5 Sf6#

 

Comments  

 
+2 #1 Seetharaman Kalyan 2015-12-23 05:29
With black rook at a4 or d1 instead of black knight d5 we will have two solutions. But we both thought that this twin is interesting!
Since corrected: The black rook should be on a3 or e1. I wrongly mentioned different squares !
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0 #2 Massimo La Rosa 2015-12-26 21:06
I'm sorry but if I trade Nd5 with a Ra4 (or Rd1) I get one only solution. I'm missing something.
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0 #3 Seetharaman Kalyan 2015-12-27 09:36
Quoting Massimo La Rosa:
I'm sorry but if I trade Nd5 with a Ra4 (or Rd1) I get one only solution. I'm missing something.

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0 #4 Massimo La Rosa 2015-12-27 14:28
Yes, Ra3 is correct for a 2 sols problem.
I prefer this release instead of the original.
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0 #5 Seetharaman Kalyan 2015-12-27 15:24
Quoting Massimo La Rosa:
Yes, Ra3 is correct for a 2 sols problem.
I prefer this release instead of the original.

I can understand. Which is better is not easy to decide!
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