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Problem 617 (617.1): Pierre Tritten & Miodrag Mladenovic - Fairy (KoBul Kings)
pierre.tritten(25.10.2015) Fairy Meredith by Pierre Tritten with two model mates after KoBul Kings transformations.
Here is also a version 617.1. with co-author Miodrag Mladenovic.
 
 
 
 
 
 
 
 
617
 
1.Bxc2(c3=rS) rSe2 2.Bxb3(e2=rQ) rQxh5(h8=rS)#
1.cxb3(c3=rQ) rQe5 2.bxc2(e5=rS) rSxg6(h8=rB)#
 
Annihilation of all white force by the same unit in each solution, Durbar, Model mates (Author)
617.1
 
KoBul Kings:when a piece (not a pawn) of his own side is captured, a King transforms into a Royal piece of the same type as the captured one. When the King is in the form of any Royal piece and there is a capture of one of the pawns of his own side, he becomes a normal King again.
 

Comments  

 
+3 #1 Miodrag Mladenovic 2015-10-25 19:31
Nice problem. You may consider also this position: 6k1.5p2.2p2b2.6s1.Kp6.Q7.qS6.r7

1.b4*a3[a4=rQ] rQa4-g4 2.a3*b2[g4=rS] rSg4*f6[g8=rB] #
1.Bf6*b2[a4=rS] rSa4-c5 2.Bb2*a3[c5=rQ] rQc5*g5[g8=rS] #

Now one bP is replaced with bR but mating positions are nicer because now black King is on g8 and rQ and Rs are guarding one more flight in mating positions.
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+1 #2 Seetharaman Kalyan 2015-10-25 20:36
NQuoting Miodrag Mladenovic:
Nice problem. You may consider also this position: 6k1.5p2.2p2b2.6s1.Kp6.Q7.qS6.r7.......
now black King is on g8 and rQ and Rs are guarding one more flight in mating positions.

Very quick to observe that both the mates cover one more diagonal and hence black king can be on 'g8' also! Well done!
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0 #3 Pierre Tritten 2015-10-26 07:59
Great version, Miodrag,I like it!
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+1 #4 Aleksey Oganesjan 2015-10-26 18:45
Interesting problem!
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