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Problem 322: Eugene Rosner - Twomover

eugenerosner(23.01.2014) Twomover with fourfold progressive black interferences by Eugene Rosner.

The author sent a better version 322.1 which you can see here. It is dedicated to David Shire.



 

322.1

    1.Bb6? (2.Bc6 A,2.Sc7 B#), 1…Ra8+!

    1.exd6 a / Sxd6 b? (2.Rc5 C#)

1…Bb6(I),Rxa7,Rc6+ 2.B(x)c6#

(a)1…Qxe8 2.Qxe6#

(b)1…Rxe5 2.Qxe5#

1…Rb6!

    1.Bb5? (2.Bc4#)

1…Bb6(I),Rxa7,Rc6+ 2.B(x)c6#

1…Rb6(II) 2.Sc7#

1…Be4 2.Qxe4#

1…Bxd8!                    (1.Ba4? b1Q!)

    1.Qf2? (2.Qxd4#)

1…Bb6(I),Rxa7,Rc6+ 2.B(x)c6#

1…Rb6(II) 2.Sc7#

1…Sf5(III) 2.Qxg2#

1…dxe5 2.Rc5# C

1…Qf4,Qxf2 2.Bxe6#

1…Sf3!

    1.Rc4! (2.Rxd4#)

1…Bb6(I),Rxa7,Rc6+ 2.B(x)c6# A

1…Rb6(II) 2.Sc7# B

1…Sf5(III) 2.Qxg2#

1…Sf3(IV) 2.Qe4#

1…dxe5 2.Rc5# C

1…Qf4,Qf2 2.Bxe6#

Fourfold Progressive Black Interferences. Nowotny, Grimshaw. Mates threatened in the early tries return as variations in the solution. Transference for 2.Qe4#. 11 mates.

(Author) 

 

Comments  

 
+1 #1 Vidadi Zamanov 2014-01-24 04:09
Good problem.
Quote
 
 
0 #2 Diyan Kostadinov 2014-02-01 16:31
The improved version 322.1 is now published. It replacing the original for the tourney.
Quote
 

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