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Problem 313: Aleksandr Pankratiev & Mikhail Gershinsky - Helpmate

pankratievgershinsky(11.01.2014) Helpmate with very rich thematic content by Pankratiev and Gershinsky. Welcome to Mikhail Gershinsky from Ukraine!



313


1.bxc6+ Kxc6 2.e6 Rxe5 3.Kxe5 d4#

1.Rxb5+ Kxc4 2.Bf3 Bxe4 3.Kxe4 d3# 

 

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+1 #1 Vitaly Medintsev 2014-01-11 11:08
A quite successful transformation of the well-known h#2 mechanism to h#3. Good problem!
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+1 #2 Vitaly Medintsev 2014-01-11 11:19
8/3pp3/2B5/1R1KpqP1/1rn1nk2/1pP5/1p1P4/2B4b saves one man.
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+1 #3 Diyan Kostadinov 2014-01-11 11:39
Here is the diagram of Vitaly's version:
prntscr.com/2iddr7
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+1 #4 Janos Mikitovics 2014-01-13 08:00
Or in a fairy form, perhaps with more harmonious start moves:
White Bc6 Ra5 Kd5 Pc3 Pd2 LBc1(6)
Black Pc7 Pf7 Pa6 Pf6 RHh6 Pe5 Pf5 Qa4 Sc4 Se4 Kf4 Pa3 Pb3 LBg2 BHh1 (15)
H#3 2 Sol.
bBishop Hopper h1, wBishop Locust c1, bBishop Locust g2, bRook Hopper h6

1.Qa4*c6 + Kd5*c6 2.RHh6-e6 Ra5*e5 3.Kf4*e5 d2-d4 #
1.Qa4*a5 + Kd5*c4 2.BHh1-f3 Bc6*e4 3.Kf4*e4 d2-d3 #

Of course, 1.Qa4*c6 + and 1.Qa4*a5 + would be good in an orthodox variant. :-)
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