(07.11.2013) Коментирайки задача номер 270 на Пиер Тритон открихме, че има интересни възможности за представяне на фееричните условия Anti Circe Clone и Circe Clone, така че решихме да публикуваме финалната версия като колективна задача.

a) 1.Sf3 Re1+ 2.Kd3 Re3# [3.Kxe3(bK=rR>h8)??]

    1.d4 Rf2 2.d3 Bd4# [3.Kxd4(bK=rB>f8)??]

b) 1.Sc2 Kc3 2.Sxa1(wB=S>g1) Rf3# [3.exf3(wR=P>f2)??]

    1.d1Q+ Kb4 2.Qxa1(wB=Q>d1) Qd2# [3.Kxd2(wQd1)??]

2x2 thematic connected solutions in the twins:

- in a) bK can not capture the mating piece because after the transformation and return

it will be selfcheck by the another white piece. Change of functions between wB/wR

- in b) two different black pieces "gives" their nature to the wB.

Four specific fairy mates. Interesting twin form with two anti-forms of the same condition.

(Authors)

Anti Circe Clone: A capturing piece (including King) takes the nature of the captured piece and then goes to its Circe rebirth square. The checking/mating piece do not take the nature of the King and its returning square is according its own nature.

Circe Clone: when a piece is captured (King excluded) it takes the nature of the capturing piece, then it reappear on its game-array square if it is empty, otherwise the captured piece vanishes. The pieces captured by King do not transforms to his nature and returns as itself.